Question

Разложите на множители 1/4a^4+2a^2b^2+4b^4

Answer 1

$boxed {(x+y)^2=x^2+2xy+y^2}\\\frac{1}{4}a^4+2a^2b^2+4b^4=underbrace {(frac{1}{2}a^2)^2}_{x^2}+underbrace {2cdot (frac{1}{2}a^2)cdot (2b^2)}_{2xy}+underbrace {(2b^2)^2}_{y^2}=(frac{1}{2}a^2+2b^2)^2$

Answer 2

Спасибо!)