Question

Разложите на множетели
16a^2+24ac+9c^2+12a+9c ​

Answer 1

16a² + 24ac + 9c² + 12a + 9c = (16a² + 24ac + 9c²) + (12a + 9c) =

= [(4a)² + 2 * 4a * 3c + (3c)²] + 3(4a + 3c) = (4a + 3c)² + 3(4a + 3c) =

=  (4a + 3c)(4a + 3c + 3)