Question

раскрой скобки и упростит выражения. 1)t² (3t-5)+4t(t²-t)= 2)-4b²(t²-b²)+3b²(b²-t²) =

Answer 1

Ответ:

1)  $7t^3-9t^2$

2)  $7b^4-7t^2b^2$

Объяснение:

1) $t^2(3t-5)+4t(t^2-t)=$

$(3t*t^2-5*t^2)+(t^2*4t-t*4t)=$

$(3t^3-5t^2)+(4t^3-4t^2)=$

$3t^3-5t^2+4t^3-4t^2=$

$7t^3-9t^2$

2) $-4b^2(t^2-b^2)+3b^2(b^2-t^2)=$

$3b^2(b^2-t^2)-4b^2(t^2-b^2)=$

$(b^2*3b^2-t^2*3b^2)-(t^2*4b^2-b^2*4b^2)=$

$(3b^4-3t^2b^2)-(4t^2b^2-4b^4)=$

$3b^4-3t^2b^2-4t^2b^2+4b^4=$

$7b^4-7t^2b^2=$

$7b^2(b^2-t^2)=$

$7b^2(b-t)(b+t)$