Ответы на вопрос
Ответил Artem112
0
Общий вид:
![f(x)=ax^2+bx+c
\
m=- frac{b}{2a}
\
n=f(m)
\
A(m;n)
\
x=m](https://tex.z-dn.net/?f=f%28x%29%3Dax%5E2%2Bbx%2Bc%0A%5C%0Am%3D-+frac%7Bb%7D%7B2a%7D+%0A%5C%0An%3Df%28m%29%0A%5C%0AA%28m%3Bn%29%0A%5C%0Ax%3Dm "f(x)=ax^2+bx+c
\
m=- frac{b}{2a}
\
n=f(m)
\
A(m;n)
\
x=m")
![f(x)=3(x-2)^2-2
\
A_1(2;-2)
\
x=2](https://tex.z-dn.net/?f=f%28x%29%3D3%28x-2%29%5E2-2%0A%5C%0AA_1%282%3B-2%29%0A%5C%0Ax%3D2 "f(x)=3(x-2)^2-2
\
A_1(2;-2)
\
x=2")
![f(x)=3-2x-x^2
\
m=- frac{-2}{-2} =-1
\
n=f(-2)=3-2cdot(-1)-(-1)^2=4
\
A_2(-1;4)
\
x=-1](https://tex.z-dn.net/?f=f%28x%29%3D3-2x-x%5E2%0A%5C%0Am%3D-+frac%7B-2%7D%7B-2%7D+%3D-1%0A%5C%0An%3Df%28-2%29%3D3-2cdot%28-1%29-%28-1%29%5E2%3D4%0A%5C%0AA_2%28-1%3B4%29%0A%5C%0Ax%3D-1 "f(x)=3-2x-x^2
\
m=- frac{-2}{-2} =-1
\
n=f(-2)=3-2cdot(-1)-(-1)^2=4
\
A_2(-1;4)
\
x=-1")
![f(x)=x^2+12x+22
\
m=- frac{12}{2} =-6
\
n=f(-6)=(-6)^2+12cdot(-6)+22=-14
\
A_3(-6;-14)
\
x=-6](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2B12x%2B22%0A%5C%0Am%3D-+frac%7B12%7D%7B2%7D+%3D-6%0A%5C%0An%3Df%28-6%29%3D%28-6%29%5E2%2B12cdot%28-6%29%2B22%3D-14%0A%5C%0AA_3%28-6%3B-14%29%0A%5C%0Ax%3D-6 "f(x)=x^2+12x+22
\
m=- frac{12}{2} =-6
\
n=f(-6)=(-6)^2+12cdot(-6)+22=-14
\
A_3(-6;-14)
\
x=-6")
Приложения:
Ответил Аноним
0
огоъ
Ответил Аноним
0
огонь Артем ту крут
Новые вопросы