При каких значениях х значения данных дробей равны
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Ответил thefinluck
0
1)
![frac{4x^2-3x}{3}= frac{x^2+5x}{2},|*6 \
2(4x^2-3x)=3(x^2+5x), \
8x^2-6x=3x^2+15x, \
5x^2-21x=0, \
x(5x-21)=0, \
left[begin{array}{ccc}x=0,\5x-21=0;end] \ frac{4x^2-3x}{3}= frac{x^2+5x}{2},|*6 \
2(4x^2-3x)=3(x^2+5x), \
8x^2-6x=3x^2+15x, \
5x^2-21x=0, \
x(5x-21)=0, \
left[begin{array}{ccc}x=0,\5x-21=0;end] \](https://tex.z-dn.net/?f=+frac%7B4x%5E2-3x%7D%7B3%7D%3D+frac%7Bx%5E2%2B5x%7D%7B2%7D%2C%7C%2A6+%5C+%0A2%284x%5E2-3x%29%3D3%28x%5E2%2B5x%29%2C+%5C+%0A8x%5E2-6x%3D3x%5E2%2B15x%2C+%5C+%0A5x%5E2-21x%3D0%2C+%5C+%0Ax%285x-21%29%3D0%2C+%5C+%0A++left%5Bbegin%7Barray%7D%7Bccc%7Dx%3D0%2C%5C5x-21%3D0%3Bend%5D++%5C)
![left[begin{array}{ccc}x=0,\x= frac{21}{5} ;end] \
left[begin{array}{ccc}x=0,\x= frac{21}{5} ;end] \](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7Dx%3D0%2C%5Cx%3D+frac%7B21%7D%7B5%7D+%3Bend%5D++%5C%0A)
![left[begin{array}{ccc}x=0,\x= 4frac{1}{5}.end]
left[begin{array}{ccc}x=0,\x= 4frac{1}{5}.end]](https://tex.z-dn.net/?f=%0A++left%5Bbegin%7Barray%7D%7Bccc%7Dx%3D0%2C%5Cx%3D+4frac%7B1%7D%7B5%7D.end%5D+)
Ответ:
2)
![frac{3x^2+7x}{4}= frac{7x^2-5x}{3}, |*12\
3(3x^2+7x)= 4(7x^2-5x), \
9x^2+21x= 18x^2-20x, \
9x^2-41x=0, \
x(9x-41)=0, \
left[begin{array}{ccc}x=0,\9x-41=0;end] \
frac{3x^2+7x}{4}= frac{7x^2-5x}{3}, |*12\
3(3x^2+7x)= 4(7x^2-5x), \
9x^2+21x= 18x^2-20x, \
9x^2-41x=0, \
x(9x-41)=0, \
left[begin{array}{ccc}x=0,\9x-41=0;end] \](https://tex.z-dn.net/?f=+frac%7B3x%5E2%2B7x%7D%7B4%7D%3D+frac%7B7x%5E2-5x%7D%7B3%7D%2C+%7C%2A12%5C+%0A3%283x%5E2%2B7x%29%3D+4%287x%5E2-5x%29%2C+%5C+%0A9x%5E2%2B21x%3D+18x%5E2-20x%2C++%5C+%0A9x%5E2-41x%3D0%2C+%5C+%0Ax%289x-41%29%3D0%2C+%5C+%0A++left%5Bbegin%7Barray%7D%7Bccc%7Dx%3D0%2C%5C9x-41%3D0%3Bend%5D++%5C+%0A)
![left[begin{array}{ccc}x=0,\x= frac{41}{9} ;end] left[begin{array}{ccc}x=0,\x= frac{41}{9} ;end]](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7Dx%3D0%2C%5Cx%3D+frac%7B41%7D%7B9%7D+%3Bend%5D+)
![left[begin{array}{ccc}x=0,\x= 4frac{5}{9} .end] left[begin{array}{ccc}x=0,\x= 4frac{5}{9} .end]](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7Dx%3D0%2C%5Cx%3D+4frac%7B5%7D%7B9%7D+.end%5D+)
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Ответ:
2)
Ответ:
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