Question

Пожалуйстааа :сссссс

Answer 1

$11.53.\\1); ; left { {{x^2+y^2-6x+8y=0} atop {x^2+y^2+2x-12y+1=10}} right. ; left { {{(x-3)^2+(y+4)^2=25} atop {(x+1)^2+(y-6)^2=36}} right. \\C_1(3,-4); ; ,; ; C_2(-1,6)\\l:; frac{x-x_1}{x_2-x_1}=frac{y-y_1}{y_2-y_1}; ; ,; ; frac{x-3}{-1-3}=frac{y+4}{6+4} ; ,; ; frac{x-3}{-4}=frac{y+4}{10}; ; ,; ; boxed {; frac{x-3}{2}=frac{y-4}{-5}; }$

$2); ; 2); ; left { {x^2+{y^2-8x+6y=0} atop {x^2+y^2-10x-6y+33=0}} right.; left { {{(x-4)^2+(y+3)^2=25} atop {(x-5)^2+(y-3)^2=1}} right. \\C_1(4,-3); ; ,; ; C_2(5,3)\\l:; frac{x-4}{5-4}=frac{y+3}{3+3}; ; ,; ; boxed {; frac{x-4}{1}=frac{y+3}{6}; }$

$11.54.; 1); ; left { {{x^2+y^2-10x-10y+30=0} atop {x^2+y^2=10}} right.; left {{-10x-10y+40=0} atop {x^2+y^2=10}} right. ; left { {{x+y=4} atop {x^2+y^2=10}} right. \\left { {{y=4-x} atop {x^2+y^2=10}} right.; left { {{y=4-x} atop {x^2+(4-x)^2=10}} right.; left { {{y=4-x} atop {2x^2-8x+6=0}} right.; left { {{y=4-x} atop {x^2-4x+3=0}} right. \\left { {{y=4-x} atop {x_1=1; ,; x_2=3}} right. ; left { {{y_1=3; ,; y_2=1} atop {x_1=1; ,; x_2=3}} right.\\A(1,3); ,; B(3,1)$

$l:; frac{x-1}{3-1}=frac{y-3}{1-3}; ; ,; ; boxed {; frac{x-1}{2}=frac{y-3}{-2}; }$

$2); ; left { {{x^2+y^2-4x-2y-15=0} atop {x^2+y^2+6x+18y-55=0}} right.; left { {{x^2+y^2=4x+2y+15} atop {x^2+y^2=-6x-18y+55}} right.; left { {{x^2+y^2=4x+2y+15} atop {4x+2y+15=-6x-18y+55}} right. \\left { {{x^2+y^2=4x+2y+15} atop {10x+20y=40}} right.; left { {{(4-2y)^2+y^2-4(4-2y)-2y-15=0} atop {x=4-2y}} right.; left { {{5y^2-10y-15=0} atop {x=4-2y}} right.\\left { {{y^2-2y-3=0} atop {x=4-2y}} right. ; left { {{y_1=-1; ,; y_2=3} atop {x_1=6; ,; x_2=-2}} right.$

$A(6,-1); ; ,; ; B(-2,3)\\l:; frac{x-6}{-2-6}=frac{y+1}{3+1}; ; ,; ; frac{x-6}{-8}=frac{y+1}{4};; ,; ; boxed{; frac{x-6}{2}=frac{y+1}{-1}; }$