Question

ПОЖАЛУЙСТА,СРОЧНО!!!
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Answer 1

$\frac{a-b}{a^{\frac{2}{3}}b^{\frac{2}{3}}}*\frac{ab^{\frac{2}{3}}+a^{\frac{2}{3}}b}{a^{\frac{2}{3}}+a^{\frac{1}{3}}b^{\frac{1}{3}}+b^{\frac{2}{3}}}=\frac{(a^{\frac{1}{3}})^{3} -(b^{\frac{1}{3}})^{3}}{a^{\frac{2}{3}}b^{\frac{2}{3}}}*\frac{ab^{\frac{2}{3}}+a^{\frac{2}{3}}b}{a^{\frac{2}{3}}+a^{\frac{1}{3}}b^{\frac{1}{3}}+b^{\frac{2}{3}}}=\\\\=\frac{(a^{\frac{1}{3}}-b^{\frac{1}{3}})*(a^{\frac{2}{3}}+a^{\frac{1}{3}}b^{\frac{1}{3}}+b^{\frac{2}{3}})}{(a^{\frac{1}{3}}b^{\frac{1}{3}})^{2}}*$$*\frac{(a^{\frac{1}{3}}b^{\frac{1}{3}})^{2}(a^{\frac{1}{3}}+b^{\frac{1}{3}})}{a^{\frac{2}{3}}+a^{\frac{1}{3}}b^{\frac{1}{3}}+b^{\frac{2}{3}}}=$

$=(a^{\frac{1}{3}}-b^{\frac{1}{3}})*(a^{\frac{1}{3}}+b^{\frac{1}{3}})=(a^{\frac{1}{3}})^{2} -(b^{\frac{1}{3}})^{2}=a^{\frac{2}{3} } -b^{\frac{2}{3} }$