Question

пожалуйста помогите ​

Answer 1

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Answer 2

$\displaystyle 7\frac{3}{4}(-2m+\frac{16}{31}n-2)-11\frac{1}{5}(-5m+\frac{5}{7}n-1)=\frac{31}{4}(-2m+\frac{16}{31}n-2)-\frac{56}{5}(-5m+\\ \\ \frac{5}{7}n-1)=-\frac{31}{2}m+4n-\frac{31}{2}+56m-8n+\frac{56}{5}=\frac{81}{2}m-4n-\frac{43}{10}$