Question

Пожалуйста помогите.

Answer 1

$\left \{ {{2x - 4(3x - 4) > 7 - 8x} \atop {x + 2(1 - x) > 3(2x - 1)}} \right. \\\\\left \{ {{2x - 12x + 16 > 7 - 8x} \atop {x + 2 - 2x > 6x - 3}} \right.\\\\\left \{ {{-10x + 16 > 7 - 8x} \atop {-x + 2 > 6x - 3}} \right.\\\\\left \{ {{-2x > -9} \atop {-7x > -5}} \right.\\\\\left \{ {{x < \frac{9}{2}} \atop {x < \frac{5}{7}}} \right.\\\\x < \frac{5}{7}$

$\left \{ {{x + 5(2x - 1) \leq -(x - 1)} \atop {2(2x + 3) + 4(x - 2)\geq 0}} \right.\\\\\left \{ {{x + 10x - 5 \leq -x + 1} \atop {4x + 6 + 4x - 8\geq 0}} \right.\\\\\left \{ {{12x \leq 6} \atop {8x\geq 2}} \right.\\\\\left \{ {{x \leq \frac{1}{2}} \atop {x\geq \frac{1}{4}}} \right.\\\\x \in [\frac{1}{4} ; \frac{1}{2}]$