Question

Помогиттееееее пожалуйста

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

Спасибо

Answer 3

$|3x^2+7x|=4\ left [{ {{3x^2+7x=-4} atop {3x^2+7x=4}} right. left [{ {{3x^2+7x+4=0} atop {3x^2+7x-4=0}} right. \3x^2+7x+4=0\D=49-4cdot 4cdot 3=1\x_{1,2}=frac{-7pm1}{6} =left |{ {{-1} atop {-frac{4}{3} }} right. \3x^2+7x-4=0\D=49+48=97\x_{1,2}=frac{-7pmsqrt{97}}{6}=left [{ {{-frac{7-sqrt{97}}{6}} atop {-frac{7+sqrt{97}}{6}}} right.$

Ответ: $-frac{4}{3};-1;-frac{7-sqrt{97}}{6} ;-frac{7+sqrt{97}}{6}$

$x^2-5|x|+4=0\(|x|)^2-5|x|+4=0\|x|=t;tgeq 0\t^2-5t+4=0\left [{ {{t=4} atop {t=1}} right. left [{ {{|x|=4} atop {|x|=1}} right. left [{ {{left [{ {{x=4} atop {x=-4}} right. } atop {left [{ {{x=-1} atop {x=1}} right. }} right.$

Ответ: $-4;-1;1;4$

Answer 4

То что мне надо) спасибо)