Question

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Answer 1

Ответ:

решение смотри на фотографии

Answer 2

$1)\frac{2}{m}-\frac{16}{m^{2}+8m }=\frac{2}{m} -\frac{16}{m(m+8)}=\frac{2(m+8)-16}{m(m+8)}=\frac{2m+16-16}{m(m+8)}=\frac{2m}{m(m+8)}=\boxed{\frac{2}{m+8}}\\\\\\2)\frac{a-2}{2a-6}-\frac{a-1}{3a-9}=\frac{a-2}{2(a-3)}-\frac{a-1}{3(a-3)}=\frac{3(a-2)-2(a-1)}{6(a-3)}=\frac{3a-6-2a+2}{6(a-3)}\\\\=\boxed{\frac{a-4}{6(a-3)}}$

$3)\frac{a^{2}+b^{2}}{2a^{2}+2ab }+\frac{b}{a+b} =\frac{a^{2}+b^{2}}{2a(a+b) }+\frac{b}{a+b} =\frac{a^{2}+b^{2}+b*2a}{2a(a+b)}=\frac{a^{2}+2ab+b^{2}}{2a(a+b)}=\\\\=\frac{(a+b)^{2}}{2a(a+b)}=\boxed{\frac{a+b}{2a} }$

$4)\frac{b+4}{ab-b^{2} }-\frac{a+4}{a^{2}-ab }=\frac{b+4}{b(a-b) }-\frac{a+4}{a(a-b) }=\frac{(b+4)*a-(a+4)*b}{ab(a-b)} =\frac{ab+4a-ab-4b}{ab(a-b)}=\\\\=\frac{4a-4b}{ab(a-b)}=\frac{4(a-b)}{ab(a-b)} =\boxed{\frac{4}{ab}}$