Question

Помогите вычислить производную функции

Answer 1

Ответ:

$y' = (2 {x}^{2} - 3)'( {x}^{2} - 2x) + ( {x}^{2} - 2x)'(2 {x}^{2} - 3) = \\ = 4x( {x}^{2} - 2x) + (2x - 2)(2 {x}^{2} - 3) = \\ = 4 {x}^{3} - 8 {x}^{2} + 4 {x}^{3} - 6x - 4 {x}^{2} + 6 = \\ = 8 {x}^{3} - 12 {x}^{2} - 6x + 6$

Answer 2

Ответ:

$y=(2x^2-3)(x^2-2x)\\\\y=2x^4-4x^3-3x^2+6x\\\\y'=8x^3-12x^2-6x+6$