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в ответе должно получится 2,25, напишите пожалуйста решение!
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Подробное решение
![( a^{2} -3a- frac{1}{a} +3)* frac{1}{a ^{2}-1 } *( a^{2} +a)= \
( frac{a ^{3}-3a ^{2}-1+3a }{a} )* frac{a ^{2}+a }{a ^{2}-1 } = \
frac{a ^{3}-3a ^{2}-1+3a }{a} * frac{a(a+1)}{(a-1)(a+1)} = \
frac{a ^{3}-3a ^{2}-1+3a }{a} * frac{a}{a-1} = frac{(a-1)(a ^{2}+a+1)-3a(a-1) }{a-1}= \
frac{(a-1)( a^{2}-2a+1) }{a-1} =a ^{2} -2a+1=(a-1) ^{2} \
(2,5-1) ^{2} =1,5 ^{2} =2,25](https://tex.z-dn.net/?f=%28+a%5E%7B2%7D+-3a-+frac%7B1%7D%7Ba%7D+%2B3%29%2A+frac%7B1%7D%7Ba+%5E%7B2%7D-1+%7D+%2A%28+a%5E%7B2%7D+%2Ba%29%3D+%5C+%0A%28+frac%7Ba+%5E%7B3%7D-3a+%5E%7B2%7D-1%2B3a++%7D%7Ba%7D+%29%2A+frac%7Ba+%5E%7B2%7D%2Ba+%7D%7Ba+%5E%7B2%7D-1+%7D+%3D+%5C+%0A+frac%7Ba+%5E%7B3%7D-3a+%5E%7B2%7D-1%2B3a++%7D%7Ba%7D+%2A+frac%7Ba%28a%2B1%29%7D%7B%28a-1%29%28a%2B1%29%7D+%3D+%5C+%0A+frac%7Ba+%5E%7B3%7D-3a+%5E%7B2%7D-1%2B3a++%7D%7Ba%7D+%2A+frac%7Ba%7D%7Ba-1%7D+%3D+frac%7B%28a-1%29%28a+%5E%7B2%7D%2Ba%2B1%29-3a%28a-1%29+%7D%7Ba-1%7D%3D+%5C+%0A+frac%7B%28a-1%29%28+a%5E%7B2%7D-2a%2B1%29+%7D%7Ba-1%7D++%3Da+%5E%7B2%7D+-2a%2B1%3D%28a-1%29+%5E%7B2%7D++%5C+%0A%282%2C5-1%29+%5E%7B2%7D+%3D1%2C5+%5E%7B2%7D+%3D2%2C25 "( a^{2} -3a- frac{1}{a} +3)* frac{1}{a ^{2}-1 } *( a^{2} +a)= \
( frac{a ^{3}-3a ^{2}-1+3a }{a} )* frac{a ^{2}+a }{a ^{2}-1 } = \
frac{a ^{3}-3a ^{2}-1+3a }{a} * frac{a(a+1)}{(a-1)(a+1)} = \
frac{a ^{3}-3a ^{2}-1+3a }{a} * frac{a}{a-1} = frac{(a-1)(a ^{2}+a+1)-3a(a-1) }{a-1}= \
frac{(a-1)( a^{2}-2a+1) }{a-1} =a ^{2} -2a+1=(a-1) ^{2} \
(2,5-1) ^{2} =1,5 ^{2} =2,25")
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