Помогите упр 36(2), 37(2), 38(2), 41(2,4)
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Ответы на вопрос
Ответил snow99
0
36)
![sqrt[3]{ - 1000} - frac{1}{4} sqrt[4]{256} = - 10 - frac{1}{4} times 4 = - 10 - 1 = - 11 sqrt[3]{ - 1000} - frac{1}{4} sqrt[4]{256} = - 10 - frac{1}{4} times 4 = - 10 - 1 = - 11](https://tex.z-dn.net/?f=+sqrt%5B3%5D%7B+-+1000%7D++-++frac%7B1%7D%7B4%7D++sqrt%5B4%5D%7B256%7D++%3D++-+10+-++frac%7B1%7D%7B4%7D++times+4+%3D++-+10+-+1+%3D++-+11)
37)
![sqrt[3]{512 times 216} = sqrt[3]{ 512} times sqrt[3]{216} = 8 times 6 = 48 sqrt[3]{512 times 216} = sqrt[3]{ 512} times sqrt[3]{216} = 8 times 6 = 48](https://tex.z-dn.net/?f=+sqrt%5B3%5D%7B512+times+216%7D++%3D++sqrt%5B3%5D%7B+512%7D++times++sqrt%5B3%5D%7B216%7D++%3D+8+times+6+%3D+48)
38)
![sqrt[4]{ {11}^{4} times {3}^{4} } = sqrt[4]{ {11}^{4} } times sqrt[4]{ {3}^{4} } = 11 times 3 = 33 sqrt[4]{ {11}^{4} times {3}^{4} } = sqrt[4]{ {11}^{4} } times sqrt[4]{ {3}^{4} } = 11 times 3 = 33](https://tex.z-dn.net/?f=+sqrt%5B4%5D%7B+%7B11%7D%5E%7B4%7D+++times++%7B3%7D%5E%7B4%7D+%7D+%3D+++sqrt%5B4%5D%7B+%7B11%7D%5E%7B4%7D+%7D+++times++sqrt%5B4%5D%7B+%7B3%7D%5E%7B4%7D+%7D++%3D+11+times+3+%3D+33)
41)
2)
![sqrt[4]{ {a}^{8} {b}^{12} } = sqrt[4]{ {a}^{8} } times sqrt[4]{ {b}^{12} } = {a}^{2} {b}^{3} sqrt[4]{ {a}^{8} {b}^{12} } = sqrt[4]{ {a}^{8} } times sqrt[4]{ {b}^{12} } = {a}^{2} {b}^{3}](https://tex.z-dn.net/?f=+sqrt%5B4%5D%7B+%7Ba%7D%5E%7B8%7D+%7Bb%7D%5E%7B12%7D++%7D++%3D+sqrt%5B4%5D%7B+%7Ba%7D%5E%7B8%7D+%7D++times++sqrt%5B4%5D%7B+%7Bb%7D%5E%7B12%7D+%7D++%3D++%7Ba%7D%5E%7B2%7D+++%7Bb%7D%5E%7B3%7D+)
4)
![sqrt[6]{ {a}^{12} times {b}^{18} } = sqrt[6]{ {a}^{12} } times sqrt[6]{ {b}^{18} } = {a}^{2} {b}^{3} sqrt[6]{ {a}^{12} times {b}^{18} } = sqrt[6]{ {a}^{12} } times sqrt[6]{ {b}^{18} } = {a}^{2} {b}^{3}](https://tex.z-dn.net/?f=+sqrt%5B6%5D%7B+%7Ba%7D%5E%7B12%7D++times++%7Bb%7D%5E%7B18%7D+%7D++%3D++sqrt%5B6%5D%7B+%7Ba%7D%5E%7B12%7D+%7D++times++sqrt%5B6%5D%7B+%7Bb%7D%5E%7B18%7D+%7D++%3D++%7Ba%7D%5E%7B2%7D++%7Bb%7D%5E%7B3%7D+)
37)
38)
41)
2)
4)
Ответил lomm321
0
Спасибо огромное вам
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