Question

помогите сроооочнооооо, пожалуйста!!!!!

Answer 1

${3}^{ {x}^{2} } times {2}^{ {x}^{2} + 1 } = frac{1}{3} sqrt{ {36}^{ {x}^{4} - 19} } \ {3}^{ {x}^{2} } times {2}^{ {x}^{2} } times 2 = frac{1}{3} times sqrt{ {6}^{2( {x}^{4} - 19) } } \ {6}^{ {x}^{2} } times 2 = frac{1}{3} times {6}^{ {x}^{4} - 19} \ {6}^{ {x}^{2} } = frac{1}{6} times {6}^{ {x}^{4} - 19} \ {6}^{ {x}^{2} } = {6}^{ {x}^{4} - 19 - 1} \ {6}^{ {x}^{2} } = {6}^{ {x}^{4} - 20 } \ {x}^{2} = {x}^{4} - 20 \ {x}^{4} - {x}^{2} - 20 = 0 \ {x}^{2} = t. : : : : : t geqslant 0 \ {t}^{2} - t - 20 = 0 \ d = {b}^{2} - 4ac = 1 - 4 times ( - 20) = 1 + 80 = 81 \ t1 = frac{1 + 9}{2} = 5 \ t2 = frac{1 - 9}{2} = - 4 \ {x}^{2} = 5 \ x = + - sqrt{5} \ 9 times sqrt{5} times ( - sqrt{5} ) = 9 times ( - 5) = - 45$
Ответ: -45