Question

Помогите срочно пж
ДАЮ МНОГО БАЛЛОВ ​

Answer 1

Объяснение:

2.

$\frac{p^2+14p+49}{6+p} :(6+\frac{13}{6+p}-p)=\frac{(p+7)^2}{6+p} :\frac{6*(6+p)+13-p*(6+p)}{6+p}=\frac{(p+7)^2}{6+p}*\frac{6+p}{36+6p+13-6p-p^2}=\\=\frac{(p+7)^2}{49-p^2} =\frac{(7+p)^2}{(7+p)*(7-p)}=\frac{7+p}{7-p} .$

3.

$\frac{3m}{m+6}+(\frac{3}{36-m^2} +\frac{1}{m^2-12m+36}) *\frac{(m-6)^2}{2}=\frac{3m}{m+6}+(-\frac{3}{m^2-36} +\frac{1}{(m-6)^2}) *\frac{(m-6)^2}{2}=\\=\frac{3m}{m+6}+(\frac{1}{(m-6)^2}-\frac{3}{(m+6)*(m-6)} ) *\frac{(m-6)^2}{2}=\frac{3m}{m+6} +\frac{1*(m+6)-3*(m-6)}{(m+6)*(m-6)^2}*\frac{(m-6)^2}{2}=\\=\frac{3m}{m+6}+\frac{m+6-3m+18}{2*(m+6)} = \frac{3m}{m+6}+\frac{-2m+24}{2*(m+6)}= \frac{3m}{m+6}+\frac{2*(-m+12)}{2*(m+6)}= \frac{3m}{m+6}+\frac{-m+12}{(m+6)}=$

$= \frac{3m}{m+6}+\frac{-m+12}{m+6} =\frac{3m-m+12}{m+6} =\frac{2m+12}{m+6} =\frac{2*(m+6)}{m+6}=2.$

4.

$(\frac{3b+1}{3b-1}-\frac{3b-1}{1+3b}):\frac{2b}{2+6b} = (\frac{3b+1}{3b-1}-\frac{3b-1}{3b+1}):\frac{2b}{2+6b} =\frac{(3b+1)^2-(3b-1)^2}{(3b-1)*(3b+1)}*\frac{2*(3b+1)}{2b} =\\=\frac{9b^2+6b+1-9b^2+6b-1}{(3b+1)*(3b-1)}*\frac{2*(3b+1)}{2b}=\frac{12b*2}{(3b-1)*2b} =\frac{12}{3b-1}.$

5.

$\frac{36a^6}{49b^5} :\frac{24a^9}{25b^4} *\frac{7a^2}{30b} =\frac{36a^6}{49b^5} *\frac{25b^4}{24a^9} *\frac{7a^2}{30b} =\frac{36a^6*25b^4*7a^2}{49b^5*24a^9*30b} =\frac{36*25*7a^8b^4}{49*24*30*a^9*b^6}=\frac{5}{28ab^2}.$