Question

Помогите с заданием!!!!!!! на фото!!!

Answer 1

$S=F(3)-F(0) = \ = ( frac{{3}^{3} }{3} - 2 times {3}^{2} + 6 times 3 - 4) - ( frac{{0}^{3} }{3} - 2 times {0}^{2} + 6 times 0 - 4) = \ = frac{{3}^{3} }{3} - 2 times {3}^{2} + 6 times 3 - 4 + 4 = \ = 9 - 18 + 18 = 9 \ \ Ответ: 9 : : (кв.ед)$