Question

Помогите с вычислением

Answer 1

2^n+1*3^n-1           2^n+1 *3^n-1    2^n+1*3^n-1

=___________=____________=_____________=3^(n-1-n+2)=3

2³ * (2*3)^n-2     2³*2^n-2 *3^n-2   2^n+1*3^n-2

(6²)^k+2                6^2k+4                       3^2k+4*2^2k+4     

=____________=_______________=_______________=2^6=64

3^2k+4*(2²)^k-1     3^2k+4 *2^2k-2      3^2k+4 *2^2k-2