Question

ПОМОГИТЕ С 12 ПРИМЕРОМ,ДАЮ ОЧЕНЬ МНОГО БАЛЛОВ,ОЧЕНЬ НУЖНО!!!!!!!!!!!

Answer 1

$Big (frac{sqrt[4]3-sqrt[4]{27}}{3-sqrt3}+frac{1+3^{-0,5}}{3^{-0,25}}Big )^2cdot Big (4-frac{6}{sqrt3}Big )^{-frac{1}{2}}=\\=Big (frac{sqrt[4]3cdot (1-sqrt[4]{3^2})}{sqrt3cdot (sqrt3-1)}+frac{1+frac{1}{sqrt3}}{frac{1}{sqrt[4]3}}Big )^2cdot Big (frac{4sqrt3-6}{sqrt3}Big )^{-frac{1}{2}}=\\=Big (frac{1-sqrt{3}}{sqrt[4]3(sqrt3-1)} +frac{sqrt[4]3cdot (sqrt3+1)}{sqrt3} Big )^2cdot Big (frac{sqrt3}{sqrt3cdot (4-2sqrt3)}Big )^{frac{1}{2}}=$

$=Big (-frac{1}{sqrt[4]3}+frac{sqrt3+1}{sqrt[4]3}Big )^2cdot frac{1}{sqrt{4-2sqrt3}} =Big (frac{sqrt3}{sqrt[4]3}Big )^2cdot frac{1}{sqrt{(1-sqrt3)^2}}=\\=(sqrt[4]3)^2cdot frac{1}{|1-sqrt3|}=frac{sqrt3}{sqrt3-1}; ;\\\star ; sqrt{4-2sqrt3}=sqrt{1+3-2sqrt3}=sqrt{1^2-2cdot 1cdot sqrt3+(sqrt3)^2}=\\=sqrt{(1-sqrt3)^2}=|underbrace {1-sqrt3}_{<0}|=-(1-sqrt3)=sqrt3-1; ; star$

Answer 2

Спасибо большое!!!!!