Question

Помогите решить
(y+3)/(4y(y-3))-(y-3)/(4y(y+3))

Answer 1

$frac{(y+3)}{4y(y-3)} + frac{(y-3)}{4y(y+3)} = frac{(y+3)(y+3) - ((y-3)(y-3))}{4y(y-3)(y+3)} + frac{ y^{2}+3y+3y+9 - (y^{2}-3y-3y+9) }{[tex] frac{y^{2}+3y+3y+9 - y^{2}+3y+3y-9}{4y(y-3)(y+3)} = frac{12y}{4y(y-3)(y+3)} = frac{3}{y^{2}-9}$}=