Question

Помогите решить x^2-4x+3>или =0

Answer 1

$x^2-4x+3 geq 0 \ \ (x-1)(x-3) geq 0$

$left {begin{array}{ccc}(x-1) geq 0\(x-3) geq 0end{array}right \ \ \ left {begin{array}{ccc}x geq 1\x geq 3end{array}right Rightarrow x geq 3$

или

$left {begin{array}{ccc}(x-1) leq 0\(x-3) leq 0end{array}right \ \ \ left {begin{array}{ccc}x leq 1\x leq 3end{array}right Rightarrow x leq 1$


Ответ: 
$x leq 1 cup x geq 3$