Помогите решить В4, В6. Пожалуйста!!!
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Ответил m11m
0
В4.
![log_{0.2}2 sqrt{3}=log_{0.2} sqrt{12} \
log_{0.2}2.5=log _{0.2} sqrt{6.25} \
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log_{0.2} sqrt{5} textgreater log_{0.2}2.5 textgreater log_{0.2}2 sqrt{3}](https://tex.z-dn.net/?f=log_%7B0.2%7D2+sqrt%7B3%7D%3Dlog_%7B0.2%7D+sqrt%7B12%7D+%5C+%0Alog_%7B0.2%7D2.5%3Dlog+_%7B0.2%7D+sqrt%7B6.25%7D+%5C+%0A+%5C+%0Alog_%7B0.2%7D+sqrt%7B5%7D++textgreater++log_%7B0.2%7D2.5+textgreater++log_%7B0.2%7D2+sqrt%7B3%7D++++ "log_{0.2}2 sqrt{3}=log_{0.2} sqrt{12} \
log_{0.2}2.5=log _{0.2} sqrt{6.25} \
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log_{0.2} sqrt{5} textgreater log_{0.2}2.5 textgreater log_{0.2}2 sqrt{3}")
Ответ:
B6.
![log_{2}x=(log_{2}27)*log_{3}2+log_{2}0.25 \
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x textgreater 0](https://tex.z-dn.net/?f=log_%7B2%7Dx%3D%28log_%7B2%7D27%29%2Alog_%7B3%7D2%2Blog_%7B2%7D0.25+%5C+%0A+%5C+%0Ax+textgreater++0 "log_{2}x=(log_{2}27)*log_{3}2+log_{2}0.25 \
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x textgreater 0")
![log_{2}x=(log_{2}3^3)*log_{3}2+log_{2}0.5^2 \
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log_{2}x=3log_{2}3*log_{3}2+2log_{2} (frac{1}{2}) \
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log_{2}x=3*log_{3}3*log_{2}2+2log_{2}2^{-1} \
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log_{2}x=3-2log_{2}2 \
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log_{2}x=3-2 \
log_{2}x=1 \
x=2](https://tex.z-dn.net/?f=log_%7B2%7Dx%3D%28log_%7B2%7D3%5E3%29%2Alog_%7B3%7D2%2Blog_%7B2%7D0.5%5E2+%5C+%0A+%5C+%0Alog_%7B2%7Dx%3D3log_%7B2%7D3%2Alog_%7B3%7D2%2B2log_%7B2%7D+%28frac%7B1%7D%7B2%7D%29++%5C+%0A+%5C+%0Alog_%7B2%7Dx%3D3%2Alog_%7B3%7D3%2Alog_%7B2%7D2%2B2log_%7B2%7D2%5E%7B-1%7D+%5C+%0A+%5C+%0Alog_%7B2%7Dx%3D3-2log_%7B2%7D2+%5C+%0A+%5C+%0Alog_%7B2%7Dx%3D3-2+%5C+%0Alog_%7B2%7Dx%3D1+%5C+%0Ax%3D2 "log_{2}x=(log_{2}3^3)*log_{3}2+log_{2}0.5^2 \
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log_{2}x=3log_{2}3*log_{3}2+2log_{2} (frac{1}{2}) \
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log_{2}x=3*log_{3}3*log_{2}2+2log_{2}2^{-1} \
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log_{2}x=3-2log_{2}2 \
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log_{2}x=3-2 \
log_{2}x=1 \
x=2")
Ответ: 2
Ответ:
B6.
Ответ: 2
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