Question

помогите решить уравнение
$3 {x}^{2} - 5x \sqrt{3} + 6 = 0$


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Answer 1

$3x^{2} -5x\sqrt{3}+6=0\\\\3x^{2}-5\sqrt{3}x+6=0\\\\D=(-5\sqrt{3})^{2}-4*3*6=75-72=3\\\\x_{1}=\frac{5\sqrt{3}-\sqrt{3}}{6}=\frac{4\sqrt{3} }{6}=\boxed{\frac{2\sqrt{3} }{3}}\\\\x_{2}=\frac{5\sqrt{3}+\sqrt{3}}{6}=\frac{6\sqrt{3} }{6}}=\boxed{\sqrt{3}}$

Answer 2

Ответ:

ниже

Объяснение:

$3x^{2} -5x\sqrt{3} +6=0\\D=25*3-4*6*3=75-72=3\\x_{1}=\frac{5\sqrt{3}+\sqrt{3} }{6} =\frac{6\sqrt{3} }{6} =\sqrt{3} \\x_{2}=\frac{5\sqrt{3}-\sqrt{3} }{6} =\frac{4\sqrt{3} }{6}= \frac{2\sqrt{3} }{3}$