Question

Помогите решить :
${y}^{2} - (7y - 6)^{2} = 0$
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Answer 1

$y^2-(7y-6)^2=0\(y-7y+6)(y+7y-6)=0\(-6y+6)(8y-6)=0\\-6y+6=0\6y=6\y_1=1\\8y-6=0\8y=6\y_2=frac{3}{4}$