Question

помогите решить
$( \sqrt{45 + \sqrt{40)} } \div \sqrt{5} - 6 \sqrt{2 = }$
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Answer 1

$(\sqrt{45}+\sqrt{40}):\sqrt{5}-6\sqrt{2}=\sqrt{\frac{45}{5}}+\sqrt{\frac{40}{5}}-6\sqrt{2}=\sqrt{9}+\sqrt{8} -6\sqrt{2}=\\\\=3+2\sqrt{2}-6\sqrt{2}=3-4\sqrt{2}$