Question

помогите решить
$frac{3x + 1}{x - 2} = frac{2x - 10}{x + 1}$

Answer 1

$frac{3x + 1}{x - 2} = frac{2x - 10}{x + 1} \ (3x+1)(x+1) = (2x-10)(x-2) \ 3x^2 + 4 x + 1 = 2 x^2 - 14 x + 20 \ x^2 + 18x - 19 = 0$
$sqrt{D} = sqrt{324+76} = sqrt{400} = 20$
$x_1 = frac{-18-20}{2} = -19 \ x_2 = frac{-18+20}{2} = 1$