Question

Помогите решить систему ривнянь пж.

Answer 1

Розв'язання завдацння додаю

Answer 2

$left{begin{array}{rcl}{3y-x =4}\{(x^2-4xy-2y^2=3} \end{array}right \\\left{begin{array}{rcl}{x =3y-4}\{(x^2-2*2xy+4y^2)-6y^2=3}\end{array}right \\\left{begin{array}{rcl}{x =3y-4}\{(x-2y)^2-6y^2=3}\end{array}right\\\left{begin{array}{rcl}{x =3y-4}\{(3y-4-2y)^2-6y^2=3}\end{array}right\\\left{begin{array}{rcl}{x =3y-4}\{(y-4)^2-6y^2=3} \end{array}right$

$left{begin{array}{rcl}{x =3y-4} \{y^2-8y+16-6y^2=3} \end{array}right\\left{begin{array}{rcl}{x =3y-4} \{-5y^2-8y+13=0} \end{array}right$

Решим уравнение -5y²-8y+13 = 0

5y²+8y-13 = 0

D = 64 + 4 * 5 * 13 = 64 + 260 = 324

y₁ = (-8+18)/10 = 1  ⇒ x₁ = 3*1-4 = -1

y₂ = (-8-18)/10 = -2.6 ⇒ x₂ = 3*(-2.6) - 4 = -7.8 - 4 = -11.8

Ответ: (-1, 1) и (-11.8, -2.6)