Question

ПОМОГИТЕ РЕШИТЬ!!! Систему неравенств
1. {2x-1<1,4-x
{3x-2>x-4
2. {5(x-2)-x>2
{1-3(x-1)<-2
3. 3(2-3p)-2(3-2p) >p
6

Срочоо

Answer 1

$displaystyleleft { {{2x-1<1,4-x} atop {3x-2>x-4}} right. left { {{2x+x<1,4+1} atop {3x-x>2-4}} right. left { {{3x<2,4} atop {2x>-2}} right.left | {{:3} atop {:2}} \left { {{x<0,8} atop {x>-1}} right. \left { {{++++++(0,8)->x} atop {-(-1)++++++>x}} right.$

$xin(-1;0,8)$

Ответ: $(-1;0,8)$

$displaystyle left { {{5(x-2)-x>2} atop {1-3(x-1)<-2}} right. left { {{5x-10-x>2} atop {1-3x+3<-2}} right. left { {{4x>12} atop {-3x<-6}} right. left |{ {{:4} atop {:(-3)}} right. \\left { {{x>3} atop {x>2}} right. left { {{-------(3)++>x} atop {-----(2)++++>x}} right. \xin(3;+infty)$

Ответ: (3;+infty)

Answer 2

А можно еще решить

Answer 3

3(2-3p) -2(3-2p) >p и 6