Question

Помогите решить пожалуйста!
(-4x^2-x+5):(4x+5)

Answer 1

$frac{( - {4x}^{2} - x + 5)} { (4x + 5)} \ { - 4x}^{2} - x + 5 = 0 \ {4x}^{2} + x - 5 = 0 \ d = sqrt{ {b}^{2} - 4ac } = sqrt{1 - 4 times 4 times ( - 5)} = sqrt{1 + 80} = sqrt{81} = 9 \ x1 = frac{ - 1 + 9}{8} = 1 \ x2 = frac{ - 1 - 9}{8} = - 1.25 \ 4x + 5 = 0 \ 4x = - 5 \ x = - 1.25 \ frac{ - {4x}^{2} - x + 5 }{4x + 5} = frac{(x - 1)(x + 1.25)}{x + 1.25} = x - 1$