Question

Помогите решить, пожалуйста

Answer 1

$\displaystyle 1)(3^-^2)^-^3*27:(-3^7)=3^6*27:(-3^7)=-3^6*3^3:3^7=-3^2=-9\\\\2)1,5a^3b^-^2*2,4a^-^1b^3=3,6a^3^-^1b^-^2^+^3=3,6a^2b^1=3,6a^2b\\\\3)(\frac{7a^-^1}{3b^-^3})^-^1*49ab^4=\frac{3b^-^3}{7a^-^1}*49ab^4=3b^-^3*7a^2b^4=21a^2b$

Answer 2

a) Ответ: 3

$( { {3}^{ - 2}) }^{ - 3} \times 27 \div ( { - 3}^{7} ) = ( \frac{1}{3} {}^{2} ) {}^{ - 3} \times 27 \div ( - 2187) = ( \frac{1}{9} ) {}^{ - 3} \times \frac{1}{81} = 27 \times \frac{1}{81} = 3$

б) Ответ: 3a²b

$1.5 {a}^{3} {b}^{ - 2} \times 2.4 {a}^{ - 1} {b}^{3} = 3.6 {a}^{2} b$

в) Ответ: 21a²b

$( \frac{ {7a}^{ - 1} }{ {3b}^{ - 3} } ) {}^{ - 1} \times 49ab {}^{4} = ( \frac{ {7b}^{3} }{3a} ) {}^{ - 1} \times 49ab {}^{4} = \frac{3a}{ {7b}^{3} } \times 49 {ab}^{4} = 21 {a}^{2} b$