Question

Помогите решить!!! Пожалуйста!!!!

Answer 1

Ответ:

1.

$y' = 4 {(x + 9)}^{3} \times ( x + 9)'= \\ = 4 {(x + 9)}^{3}$

2.

$f'(x) = ( {( {x}^{2} - 4x + 6)}^{ \frac{1}{2} } )' = \\ = \frac{1}{2} {( {x}^{2} - 4x + 6) }^{ - \frac{1}{2} } \times ( {x}^{2} - 4x + 6)' = \\ = \frac{1}{2 \sqrt{ {x}^{2} - 4x + 6} } \times (2x - 4) = \\ = \frac{x - 2}{ \sqrt{ {x}^{2} - 4x + 6 } }$

3.

$f'(x) = (( {x}^{2} - 1) ^{ - 4} )' = \\ = - 4 {( {x}^{2} - 1)}^{ - 5} \times ( {x}^{2} - 1) '= \\ = - \frac{4}{ {( {x}^{2} - 1) }^{5} } \times 2x = \\ = - \frac{8x}{ {( {x}^{2} - 1) }^{5} }$