Question

Помогите решить пожалуйста

Answer 1

Ответ:

1.x1 = 2, x2 = -2, x3 = -√2 х4 = √2

2.$frac{6(x-2,5)(x-frac{1}{3} ) }{3(x-frac{1}{3}) }$=$frac{6x-15}{3}$

3.

Объяснение:

x^4 - 6x^2 + 8 = 0

x^2 = y

y^2 - 6y + 8 = 0

D = (-6)^2 - 4(1 * 8) = 36 - 32 = 4

y1 = -(-6) - √4 / 2 * 1 = 6-2 / 2 = 4/2 = 2

y2 = -(-6)+√4/2*1 = 6+2/2 = 8/2 = 4

x^2 = y

x1 = √2

x2 = -√2

x3 = -2

x4 = 2

2. 6x^2+13x-5/3x-1

$left { {{6x^2+13x-5=0} atop {3x-1neq0}} right.$

$left { {{6x^2+13x-5=0} atop {xneq frac{1}{3} }} right.$

$6x^{2}$+13x-5=0

D=$13^{2}$-4(6*(-5))=169+120=289=$17^{2}$

$x_{1}$=$frac{-13-sqrt{289} }{2*6}$=$frac{-30}{12}$=-2,5

$x_{2}$=$frac{-13+sqrt{289} }{2*16}$=$frac{4}{12}$=$frac{1}{3}$

$frac{6(x-2,5)(x-frac{1}{3} ) }{3(x-frac{1}{3}) }$=$frac{6x-15}{3}$(х-$frac{1}{3}$ сокращается, и раскрываем скобки)