Question

Помогите решить пожалуйста

Answer 1

$sqrt{18}-sqrt{32}+sqrt{72}=sqrt{9*2}-sqrt{16*2}+sqrt{36*2}=\= sqrt{3^2*2}-sqrt{4^2*2}+sqrt{6^2*2}=3sqrt{2}-4sqrt{2}+6sqrt{2}=5sqrt{2}\\sqrt{72}+sqrt{50}-sqrt{162}=sqrt{36*2}+sqrt{25*2}-sqrt{81*2}=\=sqrt{6^2*2}+sqrt{5^2*2}-sqrt{9^2*2}=6sqrt{2}+5sqrt{2}-9sqrt{2}=2sqrt{2}\\sqrt{200}-sqrt{8}-sqrt{50}=sqrt{100*2}-sqrt{4*2}-sqrt{25*2}=\=sqrt{10^2*2}-sqrt{2^2*2}-sqrt{5^2*2}=10sqrt{2}-4sqrt{2}-5sqrt{2}=sqrt{2}$

$sqrt{128}+sqrt{18}-sqrt{98}=sqrt{8^2*2}+sqrt{3^2*2}-sqrt{7^2*2}=\=8sqrt{2}+3sqrt{2}-7sqrt{2}=4sqrt{2}\\10sqrt{2}+sqrt{8}+sqrt{50}=10sqrt{2}+sqrt{2^2*2}+sqrt{5^2*2}=\=10sqrt{2}+2sqrt{2}+5sqrt{2}=17sqrt{2}$