Question

Помогите решить..пожалуйста!!!

Answer 1

$frac{x-4}{2} - frac{7-x}{3} =2 \ frac{3(x-4)}{2*3} - frac{2(7-x)}{3*2} = frac{12}{6} \ frac{(3x-12)-(14-2x)}{6} = frac{12}{6} \ frac{3x-12-14+2x}{6} = frac{12}{6} \ 3x-12-14+2x=12 \ 3x+2x=12+14+12 \ 5x=38 \ x=7.6$

$frac{4x-1}{5} = frac{7}{3x+5} \ \ 3x+5 neq 0 \ 3x neq -5 \ x neq - frac{5}{3} \ \ (4x-1)(3x+5)=5*7 \ 12x^2-3x+20x-5=35 \ 12x^2+17x-5-35=0 \ 12x^2+17x-40=0 \ D=17^2-4*12*(-40)=289+1920=2209 \ x_1= frac{-17- sqrt{2209} }{2*12} = frac{-17-47}{24} = -frac{64}{24} =- frac{8}{3} \ x_2= frac{-17+sqrt{2209} }{2*12} = frac{-17+47}{24} =-frac{30}{24} = frac{5}{4}$