Question

Помогите решить пожалуйста

Answer 1

$(frac{y}{x-y}+frac{x}{x+y}):(frac{1}{x^2}+frac{1}{y^2})-frac{y^4}{x^2-y^2}=frac{y(x+y)+x(x-y)}{(x-y)(x+y)}:frac{y^2+x^2}{x^2y^2}-frac{y^4}{x^2-y^2}=$

 

$=frac{xy+y^2+x^2-xy}{(x-y)(x+y)}:frac{y^2+x^2}{x^2y^2}-frac{y^4}{x^2-y^2}=frac{y^2+x^2}{(x-y)(x+y)}*frac{x^2y^2}{y^2+x^2}-frac{y^4}{x^2-y^2}=$

 

$=frac{x^2*y^2}{x^2-y^2}-frac{y^4}{x^2-y^2}=frac{x^2*y^2-y^4}{x^2-y^2}=frac{y^2(x^2-y^2)}{x^2-y^2}=y^2$

 

$(sqrt{3})^2=3$

 

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