Question

Помогите решить пожалуйста!)

Answer 1

$left { {{ frac{x+3}{4} - frac{y-5}{3} = 4, } atop { y^2 + x = 13; }} right. left { {{ 3x+9 - (4y-20) = 48, } atop { y^2 + x = 13; }} right. left { {{ 3x - 4y = 19, } atop { x = 13-y^2; }} right. left { {{ 3y^2 + 4y - 20 = 0, } atop { x = 13 - y^2; }} right. \ D_1 = 2^2 - 3cdot(-20) = 64 = 8^2, \ y_1 = frac{-2-8}{3} = - frac{10}{3} = -3 frac{1}{3} , \ y_2 = frac{-2+8}{3} = frac{6}{3} = 2, \ x_1 = 13 - frac{100}{9} = frac{17}{9} = 1 frac{8}{9} , \ x_2 = 13-4=9$