помогите решить плиз умоляю помогите
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Ответил creewick
0
1)
![6^{8x+5} = 36^{1+4x} \
6^{8x+5} = 6^{2(1+4x)} \
8x+5 = 2+8x \
5 = 2](https://tex.z-dn.net/?f=6%5E%7B8x%2B5%7D+%3D+36%5E%7B1%2B4x%7D+%5C%0A6%5E%7B8x%2B5%7D+%3D+6%5E%7B2%281%2B4x%29%7D+%5C%0A8x%2B5+%3D+2%2B8x+%5C%0A5+%3D+2%0A "6^{8x+5} = 36^{1+4x} \
6^{8x+5} = 6^{2(1+4x)} \
8x+5 = 2+8x \
5 = 2")
Решений нет
2)
![5^{x^2+2x-1} = 25 = 5^2 \
x^2+2x-1 = 2 \
x^2+2x-3=0 \
D = 4+4*3= 16 \
x_1 = frac{-2+4}{2} = 1 \
x_2 = frac{-2-4}{2} = -3](https://tex.z-dn.net/?f=5%5E%7Bx%5E2%2B2x-1%7D+%3D+25+%3D+5%5E2+%5C%0Ax%5E2%2B2x-1+%3D+2+%5C%0Ax%5E2%2B2x-3%3D0+%5C%0AD+%3D+4%2B4%2A3%3D+16+%5C%0Ax_1+%3D++frac%7B-2%2B4%7D%7B2%7D+%3D+1+%5C%0Ax_2+%3D+frac%7B-2-4%7D%7B2%7D+%3D+-3 "5^{x^2+2x-1} = 25 = 5^2 \
x^2+2x-1 = 2 \
x^2+2x-3=0 \
D = 4+4*3= 16 \
x_1 = frac{-2+4}{2} = 1 \
x_2 = frac{-2-4}{2} = -3")
Ответ: x = 1; -3.
Решений нет
2)
Ответ: x = 1; -3.
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