Question

Помогите решить номер 5.9 ( 1,2)

Answer 1

№5.9
1)
$(a ^{4} b^5)^2:(a^2b^2)^3=a^8b^ {10} :a^6b^6=a^2b^4$, при а=-0.5, b=2
$(-0.5)^2*2^4=0.25*16=4$
2)
$(x^7y^4)^3:( x^{10}y^5)^2= x^{21} y^{12} : x^{20}y^ {10}=xy^2$, при х=-3, у=$frac{2}{3}$
$-3*( frac{2}{3}) ^{2} =-3* frac{4}{9}=- frac{3*4}{9}=- frac{1*4}{3}=-1 frac{1}{3}$