Question

Помогите решить!!!!!n*(n-2)-(n-2)*(n-4)

Answer 1

n(n-2)-(n-2)(n-4)=(n-2)(n-(n-4))=(n-2)(n-n+4)=4(n-2)=4n-8

Answer 2

n*(n-2)-(n-2)*(n-4)=0 n^2-2n-(n^2-4n-2n+8=0 n^2-2n-n^2+4n+2n-8=0 4n-8=0 4n=8 n=8:4 n=2