Question

помогите решить log5(25y) при log5y=-10,2

Answer 1

$log_525+log_5y=2+(-10,2) = -8,2$

Answer 2

$log_{5}y=-10{,}2medskip\log_{5}25y=log_{5}25+log_{5}y=log_{5}5^2-10{,}2=2-10{,}2=-8{,}2$