Question

Помогите решить 7 и 8

Answer 1

$displaystylettboxed{7}\\ (4x^2-2xy+y^2)-(*)=3x^2+3xy\\(*)=(4x^2-2xy+y^2)-(3x^2+3xy)\\ (*)=4x^2-2xy+y^2-3x^2-3xy\\ bold{(*)=x^2-5xy+y^2}\\\ boxed{8}\\ 2a^2d^3=7 Rightarrow a^2d^3=frac{7}{2}\\\ a) -6a^2d^3=-6cdotfrac{7}{2} = -21\\\ b) 2a^4d^6=2{(a^2d^3)}^2=2cdot bigg(frac{7}{2}bigg)^2=2cdotfrac{49}{4} =frac{49}{2} =24frac{1}{2} =24.5$