Question

Помогите решить 6.1
6.2

Answer 1

$6.1); ; Big (frac{5a^3b^5}{3c^7d^2}Big )^4=frac{625; a^{12}; b^{20}}{81; c^{28}; d^8}\\Big (frac{2x^{-3}y^2}{3x^4y^{-5}}Big )^{-2}=Big (frac{2y^7}{3x^7}Big )^{-2}=Big (frac{3x^7}{2y^7}Big )^2=frac{9; x^{14}}{4; y^{14}}=frac{9}{4}cdot Big (frac{x}{y}Big )^{14}$

$Big (frac{5, u^{-4}v^3, t^{-5}}{2^{-2}, u^{-3}, v^{-1}, t^3}Big )^{-3/2}=Big (frac{5, u^{-1}, v^{4}, t^{-8}}{frac{1}{4}}Big )^{-3/2}=(20)^{-3/2}, u^{3/2}, v^{-6}, t^{12}=frac{u^{3/2}, t^{12}}{20^{3/2}, v^6}\\Big (frac{x^{-1/2}, y^{2/3}, z^2}{x^2, y^{-1/3}, z^{1/3}}Big )^{1/2}=Big (frac{ycdot z^{5/3}}{x^{5/2}}Big )^{1/2}=frac{y^{1/2}, z^{5/6}}{x^{5/4}}\\6.2); ; sqrt9cdot sqrt{16}-sqrt{25}cdot sqrt{36}=3cdot 4-5cdot 6=12-30=-18\\sqrt{75^2-2cdot 75cdot 74+74^2}=sqrt{(75-74)^2}=sqrt{1^2}=1}$