Question

Помогите решить ................................

Answer 1

f'(x)=1/(㏑3*(x-1))

g'(x)=2*(3ˣ+3⁻ˣ)*(3ˣ*㏑3+(1/3ˣ)*㏑3)=2*㏑3*(3ˣ+3⁻ˣ)*(3ˣ+3⁻ˣ)=

2*㏑3*(3ˣ+3⁻ˣ)²=㏑9*(3ˣ+3⁻ˣ)²