Question

помогите решить
3x²+4x-4=0
8x²-2x-3=0
4x²+4x-3=0

Answer 1

3x²+4x-4=0

(3x-2)(x+2) = 0

x₁ = 2/3, x₂ = -2

8x²-2x-3=0

(4x-3)(2x+1) = 0

x₁ = 3/4, x₂ = =1/2

4x²+4x-3=0

(2x+3)(2x-1) = 0

x₁ = -1 1/2, x₂ = 1/2