Помогите решить 1 b, 2, 4 b
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Ответил sedinalana
0
1b
![sqrt[3]{(4+2 sqrt{2})(4-2 sqrt{2} ) } = sqrt[3]{16-8} = sqrt[3]{8} =2 sqrt[3]{(4+2 sqrt{2})(4-2 sqrt{2} ) } = sqrt[3]{16-8} = sqrt[3]{8} =2](https://tex.z-dn.net/?f=+sqrt%5B3%5D%7B%284%2B2+sqrt%7B2%7D%29%284-2+sqrt%7B2%7D+%29+%7D+%3D+sqrt%5B3%5D%7B16-8%7D+%3D+sqrt%5B3%5D%7B8%7D+%3D2)
2a
![a ^{-3} *a^2b ^{2/3} /b ^{1/3} =a ^{-1} b ^{1/3} = sqrt[3]{b} /a a ^{-3} *a^2b ^{2/3} /b ^{1/3} =a ^{-1} b ^{1/3} = sqrt[3]{b} /a](https://tex.z-dn.net/?f=a+%5E%7B-3%7D+%2Aa%5E2b+%5E%7B2%2F3%7D+%2Fb+%5E%7B1%2F3%7D+%3Da+%5E%7B-1%7D+b+%5E%7B1%2F3%7D+%3D+sqrt%5B3%5D%7Bb%7D+%2Fa)
2b

4b
2/3<1⇒
2a
2b
4b
2/3<1⇒
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