Question

Помогите решить
1) 1-cos2x\tg(x^2)
2) 3sin2x-4sin5x\5sin3x+sin5x

Answer 1

Ответ:

1)

$\frac{1 - cos2x}{ ({tgx})^{2} } =$

$= \frac{( {cosx})^{2} +( {sinx})^{2} - (( {cosx})^{2} - (s {sin})^{2} ) }{ ({tgx})^{2} } =$

$= \frac{2( {sinx})^{2} }{ {(tgx)}^{2} } =$

$= \frac{2 {(sinx)}^{2} }{ \frac{ {(sinx)}^{2} }{ {(cosx)}^{2} } } = 2 {(cosx)}^{2}$

Ответ:

$2 {(cosx)}^{2}$