Question

помогите!!! пжпжпжпж ​

Answer 1

$\displaystyle 1)(x-2)^2-(x-1)(x+1)=0\\x^2-4x+4-(x^2-1)=0\\x^2-4x+4-x^2+1=0\\-4x+5=0\\-4x=-5\\\\ x=\frac{5}{4}=1\frac{1}{4}=1,25\\\\ 2) (x+3)^2+(2-x)(x+2)=1\\x^2+6x+9+(2-x)(2+x)=1\\x^2+6x+9+4-x^2=1\\6x+13=1\\6x=1-13\\6x=-12\\x=-2\\\\ 3) (2x+1)^2-3(x-5)^2=(x+3)(x-3)+3\\4x^2+4x+1-3(x^2-10x+25)=x^2-9+3\\4x^2+4x+1-3x^2+30x-75=x^2-6\\x^2+34x-74=x^2-6\\34x-74=-6\\34x=-6+74\\34x=68\\x=2$