Question

помогите пжп

(6x-3)(3-x)=0

Answer 1

$18x - 6 {x}^{2} - 9 + 3x = 0 \\ - 6 {x}^{2} + 21x - 9 = 0$

D=21²-4×(-6)×(-9)=441-216=225=15²

$x1 = \frac{ - 21 + 15}{2 \times ( - 6)} = \frac{ - 6}{ - 12} = \frac{1}{2} = 0.5$

$x2 = \frac{ - 21 - 15}{2 \times ( - 6)} = \frac{ - 36}{ - 12} = 3$

Ответ: x1=0,5; x2=3.