Question

помогите пж срочно даю 100 и тот кто правильно напишет таму ещё 50 дам

Answer 1

$x - 32 = - 7(x - 8) \ x - 32 = - 7x + 56 \ x + 7x = 56 + 32 \ 8x = 88 \ x = 88 div 8 \ x = 11$

$3(4y - 8) = 3y - 6 \ 12y - 24 = 3y - 6 \ 12y - 3y = - 6 + 24 \ 9y = 18 \ y = 18 div 9 \ y = 2$

$- 3.2n + 4.8 = - 2(1.2n + 2.4) \ - 3.2n + 4.8 = - 2.4n - 4.8 \ - 3.2n + 2.4n = - 4.8 - 4.8 \ - 0.8n = - 9.6 \ n = - 9.6 div ( - 0.8) \ n = - 96 div ( - 8) \ n = 12$

$x - 5(0.8x - 1.2) = 7.2 \ x - 4x + 6 = 7.2 \ - 3x = 7.2 - 6 \ - 3x = 1.2 \ x = 1.2 div ( - 3) \ x = - 0.4$

$- (5x - 8) = 25 - (11x - 19) \ - 5x + 8 = 25 - 11x + 19 \ 11x - 5x = 44 - 8 \ 6x = 36 \ x = 36 div 6 \ x = 6$

$frac{3}{4} x - 1.25 = frac{9}{8} x - frac{1}{8} : : | times 8 \ 2 times 3x - 10 = 9x - 1 \ 6x - 9x = - 1 + 10 \ - 3x = 9 \ x = 9 div ( - 3) \ x = - 3$

$frac{1}{5} ( frac{5}{9} x + 5) - frac{1}{7} ( frac{7}{6} x + 2 frac{1}{3} ) = 2 \ frac{5x}{5 times 9} + frac{5}{5} - frac{7x}{7 times 6} - frac{7}{7 times 3} = 2 \ frac{x}{9} + 1 - frac{x}{6} - frac{1}{3} = 2 : : : | times 18\ 2x + 18 - 3x - 6 = 36 \ - x = 36 - 12 \ - x = 24 \ x = - 24$

Answer 2

Решить уравнения:

1)

$x-32=left(x-8right)left(-7right)\x-32=-7x+56\x+7x=56+32\8x=88\frac{8x}{8}=frac{88}{8}\x=11$

2)

$3(4y-8)=3y-6\12y-24=3y-6\12y-3y=-6+24\9y=18\frac{9y}{9}=frac{18}{9}\y=2$

3)

$-3.2n+4.8=-2cdot (1.2n+2.4)\-3.2n+4.8=-2.4n-4.8 |: cdot(-10)\32n-48=24n+48\32n-24n=48+48\8n=96\frac{8n}{8}=frac{96}{8}\n=12$

4)

$x-5cdot (0,8x-1.2)=7.2\x-(4x-6)=7.2\x-4x+6=7.2\-3x=7.2-6\-3x=1.2\frac{-3x}{-3}=frac{1.2}{-3}\x=-0.4$

5)

$x-(5x-8)=25-(11x-19)\-5x+8=25-11x+19\-5x+11x=44-8\6x=36\frac{6x}{6}=frac{36}{6}\x=6$

6)

$frac{3}{4}x-1.25=frac{9}{8}x-frac{1}{8} \\frac{3}{4}x-frac{9}{8}x=-frac{1}{8} +frac{5}{4} \\frac{2cdot 3-9}{8}x =frac{5cdot 2-1}{8} \\-frac{3}{8}x = frac{9}{8} | :cdot (-8)\\24x=-72\frac{24}{24}x = -frac{72}{24}\x=-3$

7)

$frac{1}{5}(frac{5}{9}x+5)-frac{1}{7}(frac{7}{6}x+2frac{1}{3} ) = 2\\frac{1}{9}x+1-frac{1}{6}x-frac{1}{3}=2\\frac{1}{9}x-frac{1}{6}x=2-1+frac{1}{3} :big|cdot 18\\2x-3x=18+6\-x=24 :big|cdot (-1)\x=-24$