Question

Помогите пж не могу сделать​

Answer 1

№7,14

$\displaystyle\\4^{-2}x\leq 12,75-4^{-1}\\\\\frac{1}{4^2}x\leq 12,75- \frac{1}{4^1} \\\\\frac{1}{16}x\leq 12,75-\frac{1}{4}\\\\\frac{1}{16}x\leq 12,75-0,25 \\\\\frac{1}{16}\leq 12,50\\\\x\leq 12,50:\frac{1}{16}\\\\x\leq 12,50*16\\\\x\leq 200$

x ∈ ( -∞ ; 200 ]

наибольшее целое число, удовлетворяющее неравенству = 200

$\displaystyle\\12^2+3^4x\leq 8^2x+6^{-1}\\\\144+81x\leq 64x+\frac{1}{6^1} \\\\81x-64x\leq \frac{1}{6}-144\\\\17x\leq \frac{1}{6}- \frac{864}{6}\\\\17x\leq -\frac{863}{6} \\\\x\leq -\frac{863}{6}:17\\\\x\leq -\frac{863}{6}*\frac{1}{17}\\\\x\leq -\frac{863}{102} \\\\x\leq -8\frac{47}{102}$

x ∈ ( -∞ ; $-8\frac{47}{102}$ ]

наибольшее целое число, удовлетворяющее неравенству = -8

$\displaystyle\\4^{-1}x\leq 13^0-12^{-1}-3x\\\\\frac{1}{4^1}x\leq 1-\frac{1}{12^1}-3x\\\\\frac{1}{4}x+3x\leq 1-\frac{1}{12}\\\\\frac{1}{4}x +\frac{12}{4}x\leq \frac{12}{12}-\frac{1}{12}\\\\\frac{13}{4}x\leq \frac{11}{12}\\\\x\leq \frac{11}{12}:\frac{13}{4}\\\\x\leq \frac{11}{12} *\frac{4}{13}\\\\x\leq \frac{11}{3*13} \\\\x\leq \frac{11}{39}$

x ∈ ( -∞ ;  $\frac{11}{39}$ ]

наибольшее целое число, удовлетворяющее неравенству = 0